Diode laser correction

Michael Topp <mrt@sas.upenn.edu> Wed, Aug 12, 2009 at 11:15 AM
To: Grace Kim
See below:

Grace Kim wrote:
Dr. Topp,
Could you check this over and see if my explanation is more accurate?

I think my misconception stemmed from a misunderstanding of how pumping occurs in a diode laser.

*P and N-doping & a natural voltage/ "population inversion" in a p-n junction*
I did not realize that the p-n junction of a diode already has an artificially created population inversion because of the structure of a n-doped and p-doped semiconductor.  The n-doped semiconductor is made by doping with atoms with an extra electron, which must occupy the conduction band because the valence band is fully occupied.  In the p-doped semiconductor, there are "holes" or vacancies in the valence band due to doping with electron deficient atoms.
I would say that the condition for a population inversion is created by bringing together n- and p-type doped materials.

*Pumping the diode with an electrical current*
As the conduction band electrons relax and occupy the "holes," the population inversion can only be maintained by applying a current that removes electrons from the p-type semiconductor and replenishes the electrons in the n-type semiconductor (i.e. applying a positive current to the p-type semiconductor and a negative current to the n-type semiconductor). An electrical current is only used to pump the diode laser to maintain the original pre-existing population inversion and allow for continuous lasing action.  Without the current, the extra electrons from the n-conductor would relax into the holes of the p-conductor and produce an electrically neutral region (effectively quenching the ability to produce light).
There is a single definable current although there are two types of charge carrier.  What you apply is a VOLTAGE, or a POTENTIAL DIFFERENCE and not a current.   Essentially OK, with a significant caveat.

What you actually describe is an LED and not yet a diode laser.  In the LED, you simply need to make electrons fall into holes to generate light.  It so happens that the population is naturally inverted, but this asset is not used in the LED.

In the laser, you need to have the population inversion as part of the amplification process.  For the laser, of course, you further need to form the device so that the junction becomes part of an optical resonator.

*An analogy, kind of?*
Rightly or wrongly, I kind of think of the application of electrical current to a diode as similar (not equivalent!) to the use of a salt bridge in a voltaic cell--it keeps the charges moving so that things don't fizzle out and die.
I wouldn't go there.  The salt bridge is passive like a wire, except that there is more than one type of charge carrier.  The battery applied to an LED is a power source, where a chemical reaction generates a suitable potential difference needed to drive a current through a circuit.

--
Michael Topp             Professor, Department of Chemistry, University of Pennsylvania
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